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If you accidentally move the master file from where it was when you imported the image as a referenced file or changed it in some way, Aperture may not know how to find it. We ve noticed that Aperture 3 is far more able to locate files by itself than earlier versions, but it s still possible that it may not be able to locate the master. In that case you have to tell it where to look. To reconnect one or more missing master files, do the following:

0x02000000@

(4.28)

Y = 0~80800000 X . @

1. 2. 3.

idea is that the most fit individuals should not be distorted through application of mutation - thereby ensuring that the good characteristics of the fit individuals persevere. Elitism is an operator that copies a set of the best individuals to the next generation, hence ensuring that the maximum fitness value does not decrease from one generation to the next. Selection operators are used to select these elitist individuals. Several selection techniques exist, divided into two classes: Explicit fitness remapping, where the fitness values of each individual is mapped into a new range, e.g. normalization to the range [0, 1]. The mapped value is then used for selection. Implicit fitness remapping, where the actual fitness values of individuals are used for selection. Goldberg and Deb [Goldberg and Deb 1991] presented a comparison of these selection schemes. Based on this comparison, Beasley et al. concluded that selection schemes from both classes perform equally well with suitable adjustment of parameters [Beasley et al. 1993]. Therefor, no method is absolutely superior to the other. A summary of the most frequently used selection operators are given in the subsections below.

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Y=L@R,

(4.29)

Reconnect the hard drive containing the referenced masters. Select the Project or Album containing the referenced files. Choose File Locate Referenced Files. The dialog shown in Figure 3.27 appears. On the left is a list of the names of hard drives where you re storing referenced masters, as well as how many masters were found and any that weren t located. The next column tells you the specific location of the master file for each referenced file.

Figure 419: FEAL-4 last round We are now in a position t o solve for putative values of subkey K3 Suppose we have one pair of chosen plaintexts PO and PI that satisfy (427), and we have the corresponding ciphertexts Co and C1 For these ciphertexts, we compute 2 from (428) Then we compute Yo and Y (corresponding t o Co 1 and C1, respectively) via (429) There are 232 possible values for subkey K3 Denote a putative value of K3 as K3 We know YO from (429) Then given k3, can determine 2 we 0 (a putative value for ZO), 2 1 , (a putative value for 20).

"^ft^ dE d -Ti6yjzi (3.39)

If we find and that 2 = 20@21, then I 3 is a possible value for K3 and we save it; otherwise we know that K3 # K 3 and we discard this choice of K 3 Using only a single pair of chosen plaintexts, we will find many putative l that pass this test, 3 but with four pairs, we expect only the correct K3 t o survive; see Problem 29 Following the method described in the previous paragraph, the work factor t o recover K3 is on the order of 232 and four pairs of chosen plaintexts are required However, due t o the structure of the F function, it, is possible t o reduce this work factor t o about 217 as discussed below But first we require some additional notation.

4. 5.

As in other sections of this book, we adopt the convention that bits are numbered from left t o right, beginning with 0, and we use the notation (A)i..j, where j > i, for the string of bit of length j-z+l beginning with bit i and ending with bit j of A Let z be the all-zero byte Then for a 32-bit word A , define.

M ( A ) = M(ao, a1, a21 a3) = ( 2 , a0 CB a1,a2 CE a3, 2).

If direct weights from the input to the output layer are included, the following additional weight updates are needed:

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